![]() ![]() The notation in blocks of 5 is an indication for the mod 10 variant, since with the mod 2 variant you usually just handle binary data 01237552353112712189874791592 Ciphertextħ0822636828325880805258368760 Text (encoded) If you happen to have got your fingers on the "let's do this by hand" or schoolbok variant, it is not, basically because it handles values mod 10 and not mod 2, leading to encryption is +. for the binary variant it surely is the same operation, a simple XOR the notable difference, to tell those two apart, is that there is a key involved here.Äepending on which variant of vernam you are handling, encryption and decryption may be the same or not. > first of all, we are talking about encryption not encoding (at the first step). "can you confirm me that the algorithm is the same for encoding and decoding?"
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